Question

P(x)=6x2+7x-5. g(x)=2x+3, if p(x)=g(x)q(X)+r(x), then find q(x) and r(x)​

Answer 1

If p(x)=g(x)q(X)+r(x), then q(x) and r(x) is (3x-1) & (-2) respectively.

Step-by-step explanation:

Given data:

p(x)=6x2+7x-5

g(x)=2x+3

p(x)=g(x)q(X)+r(x)

To find:

The value of q(x) & r(x)

Solution:

From the given equation:

p(x)=g(x)q(x) + r(x)

we can write that,  

p(x) = dividend

g(x) = divisor

q(x) = quotient

r(x) = remainder

So, to find the q(x) & r(x) as asked, we just need to divide the given values of p(x) by the values of g(x).

Therefore,

2x-3 ) 6x² + 7x – 5 ( 3x - 1

           6x² + 9x

           -      -

----------------------------------------

                    -2x – 5

                     - 2x – 3

                     +       +

-------------------------------------------  

                                -2

----------------------------------------------

Thus,

The value of,

q(x) = 3x - 1

And,

r(x) = - 2

Hope this is helpful!!!!!

Answer 2

Step-by-step explanation:

here is the answer of your question hope it's helpful for you