P(x)=6x2+7x-5. g(x)=2x+3, if p(x)=g(x)q(X)+r(x), then find q(x) and r(x)
Answers
If p(x)=g(x)q(X)+r(x), then q(x) and r(x) is (3x-1) & (-2) respectively.
Step-by-step explanation:
Given data:
p(x)=6x2+7x-5
g(x)=2x+3
p(x)=g(x)q(X)+r(x)
To find:
The value of q(x) & r(x)
Solution:
From the given equation:
p(x)=g(x)q(x) + r(x)
we can write that,
p(x) = dividend
g(x) = divisor
q(x) = quotient
r(x) = remainder
So, to find the q(x) & r(x) as asked, we just need to divide the given values of p(x) by the values of g(x).
Therefore,
2x-3 ) 6x² + 7x – 5 ( 3x - 1
6x² + 9x
- -
----------------------------------------
-2x – 5
- 2x – 3
+ +
-------------------------------------------
-2
----------------------------------------------
Thus,
The value of,
q(x) = 3x - 1
And,
r(x) = - 2
Hope this is helpful!!!!!
Step-by-step explanation:
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