Math, asked by Ayush9012534119, 1 year ago

p(x)=8x^3-6x^2-2x^2+5x-1;x=-1/2

Answers

Answered by yogesh13jain
1
8x^3-8x^2+5x-1=0
x=-1/2
p(-1/2)=8(-1/2)^3-8(-1/2)^2+5(-1/2)-1
p(-1/2)=-1-2-5/2-1
p(-1/2)=-13/2

yogesh13jain: isn't this polynomial a bit strange??
yogesh13jain: it has two like terms
yogesh13jain: of x^2
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