Question

p(x)=ax2+bx+c. if a+b+c=0 then find one of its zero

Answer 1

P(x ) = ax² + bx + c
put x = 1

P(1) = a + b + c
but a + b + c = 0
so, P(1) = 0
so, x = 1 is the root of P(x )

Answer 2

Answer:

x=1 is one of the zero of p(x) .

Step-by-step explanation:

Given p(x)= $a x^{2}+b x+c$

The above mentioned equation is in the quadratic form

a+b+c =0

Consider the given eqn

p(x)= $a x^{2}+b x+c$

The above mentioned equation is the general form of the polynomial where a, b, c are variables and x is a constant

Put x=1 in the above equation we get

p(1)=a+b+c

But we know that a+b+c = 0

Therefore p(1)=0

So when x=1 p(1)=0

Therefore x=1 is the root of p(x)  

x=1 is one of the zero of p(x)

Here p represents the polynomial