p(x) = ax2+ bx + c is a quadratic polynomial then what is relation of c/a with zeroes of p(x)?
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Answered by
15
Answer:
let x and y be the zeroes of the polynomial p(x) = ax2+ bx + c
then c/a = x×y
i.e c/a is the product of the zeroes
Answered by
5
Step-by-step explanation:
in quadratic polynomial ax² + bx + c,
sum of the zeros = -b/a
product of zeros = c/a
therefore the relation of c/a with zeros of p(x)
is, c/a = product of the zeros
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