P(x)=ax3+bx2+cx+d=0 if x+1 is a factor then prove a+c=c+d
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p(x)=ax³+bx²+cx+d=0
given: x+1 is factor.
=> x+1=0; x=-1
now substitute x value in p(x).
P(-1)=a(-1)³+b(-1)²+c(-1)+d =0
=> -a+b-c+d=0
after rearranging,
=>a+c=b+d
Step-by-step explanation:
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