p(x) in x3 _4x2 where x=3
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p(x) = x³-4x²
put x = 3 in p(x)
p(3) = (3)³ - 4 × (3)²
= 27 - 36
= -9
put x = 3 in p(x)
p(3) = (3)³ - 4 × (3)²
= 27 - 36
= -9
Iamkeetarp:
27- 36 = ????
Answered by
0
p(x) = x ^3 - 4x^2
when x = 3
p(3) = 3^3 - 4 (3)^2
p(3) = 27 - 36
p(3) = -9
Hope it heleped you...
when x = 3
p(3) = 3^3 - 4 (3)^2
p(3) = 27 - 36
p(3) = -9
Hope it heleped you...
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