Question

P(x) is (x-2)^2 +(x+2)^2​

Answer 1

P(x) is (x-2)^2 +(x+2)^2

Answer 2

Answer:

P(x)=(x-2)²-(x+2)²

This is in the form of a²-b²

p(x)=(x-2+x+2)(x-2-(x+2))

p(x)=2x(x-2-x-2)

p(x)=2x(-4)

p(x)=-8x

p(x)=0

-8x=0

x=0

x=0 is the zero of the polynomial p(x)

Step-by-step explanation:

Answer:

The zero of the polynomial is 0.

Step-by-step explanation:

Given polynomial p(x) =

………………equation 1

Apply the formula

Here in the above equation 1

a= (x-2)    

b=(x+2)    

By substituting the values of a and b in the equation 1

We get= [(x-2) +(x+2)] [(x-2) -(x+2)]=0

[In the above step while simplifying we have to be careful with the + and – signs]

Simplify the above equation

(x-2+x+2)(x-2-x-2)=0

(2x)(-4)=0

-8x=0

x=0

Therefore p(x)= is 0

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