P (x)= kx^2-3x+2k . Given alpha + beta = alpha.beta , then find the value of k and also roots of solution
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P(x) = kx²-3x+2k
for the quadratic equation a=k,
b= -3 , c=2k
Let the roots alpha and beta be equal to x1 and x2 respectively.
As we know sum of roots is equal to -b / a and the products of the roots is equal to c/a.
Therefore , x1+x2 = -b/a and
x1.x2= c/a
x1+x2 = 3/k and x1.x2= 2
Given,
x1+x2= x1.x2
=> 3/k= 2
=> k= 3/2
Now, P(x) = 1.5x²-3x+3
D= b²-4ac
= -9
Value of D<0 so the roots of the equation will be imaginary.
x1 and x2 are imaginary.
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