Math, asked by dakshita3086, 1 year ago

P (x)= kx^2-3x+2k . Given alpha + beta = alpha.beta , then find the value of k and also roots of solution

Answers

Answered by ParvezShere
5

P(x) = kx²-3x+2k

for the quadratic equation a=k,

b= -3 , c=2k

Let the roots alpha and beta be equal to x1 and x2 respectively.

As we know sum of roots is equal to -b / a and the products of the roots is equal to c/a.

Therefore , x1+x2 = -b/a and

x1.x2= c/a

x1+x2 = 3/k and x1.x2= 2

Given,

x1+x2= x1.x2

=> 3/k= 2

=> k= 3/2

Now, P(x) = 1.5x²-3x+3

D= b²-4ac

= -9

Value of D<0 so the roots of the equation will be imaginary.

x1 and x2 are imaginary.

Answered by kingraj14
2

Answer:

uper wala dekh le mader chod

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