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verification ________
p (x) =x^2 -x -6
p (-2) =(-2)^2 -(-2) -6
= 4 +2 -6
=0________(1)
p(3) =(3)^2 -3 -6
=9 -3 -6
=0________(2)
here in both equation the value of p(x) is 0
Hence -2 and 3 are the zeros of the polynomial. Ans☺️☺️☺️☺️☺️
p (x) =x^2 -x -6
p (-2) =(-2)^2 -(-2) -6
= 4 +2 -6
=0________(1)
p(3) =(3)^2 -3 -6
=9 -3 -6
=0________(2)
here in both equation the value of p(x) is 0
Hence -2 and 3 are the zeros of the polynomial. Ans☺️☺️☺️☺️☺️
kkaarrttiikk:
thank you very much
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Hope this helps you ☺☺☺☺
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