Question

p(x)= kx³- 3x²-8
Q(x)= 3x³-5x+k
are divided by x-2 and leaves the remainder find k

Answer 1

Both are leaving same remainder means they are equal.

kx³-3x²-8=3x³-5x+k

Now,Put value of x-2 in place of x

x-2=0

x=2

k(2)³-3(2)²-8=3(2)³-5(2)+k

k(8)-3(9)-8=3(8)-5(2)+k

8k-27-8=24-10+k

8k-k=14+35

7k=49

k=49/7

k=7.