Question

P(x)=m²-3m+1, find the value of p(1) and p(2)

Answer 1

$\huge\mathfrak{Solution:-}$

P(x)=m²-3m+1

p(1)=1-3+1=-1

P(2)=4-6+1=-1

$\huge\boxed{p(1)=-1\:and\:p(2)=-1}$

Answer 2

Given :-

p(x) = m² - 3m + 1

We have to find p (1) and p(2).

• Put x = 1 in equation.

→$p( 1) = (1)^2 -3 \times 1 +1$

→$p(1) = 1 -3 + 1$

→$p(1) = 2 -3$

→$p(1) = -1$

• at x = 1 p(1) is -1.

• Put x = 2 in equation.

→$p(2) = 2^2 - 3 \times 2 +1$

→$p(2) = 4 -6 +1$

→$p(2) = 5-6$

→$p(2) = -1$

• at x = 2 p(2) is also -1