Question

p(x)=t2-4t+3findalpha4beta3+alpha3beta4

Answer 1

p(x) = t^2 -4t +3
here alpha + beta = 4
and alpha× beta = 3
then:
=alpha^4 beta^3 + beta^4 alpha^3
= alpha^3 beta^3 ( alpha + beta)
= (alpha× beta)^3 × ( alpha + beta)
Putting values:
= 3^3 × 4
= 27 × 4
= 108
This is your answer friend...