Question

p(x) = (x-1) (x+1) if x=0​

Answer 1

Answer:

Hii Everyone

Step-by-step explanation:

(x – 1)x (x + 1) = x2 – 1 (x – 1) (x + 1) (x + 2)=(x2 – 1) (x + 2) = x3 – x + 2x2 – 2 = x3 + 2x2 – x – 2 = 0 p(x) = x + 2x – x – 2 = 0 p(1) =1 + 2 – 1 – 2 = 0 p(–1) = – 1 + 2 + 1 – 2 = 0 p(–2) = – 8 + 8 + 2 – 2 = 0 1, – 1, – 2 are the solutions of the equation p(x) = 0.

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