Question

p(x) = (x-1) (x + 1), then the value
p (2) p (1) - p (o)​

Answer 1

Answer:

p(x)=(x-1)(x+1)

p(x)=x^2-1

Now,

p(0)=0^2-1

=0-1

=-1

Also,

p(1)=1^2-1

=1-1

=0

And,

p(2)=2^2-1

=4-1

=3

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Answer 2

Answer:

According to the formula,

(a+b) (a-b) = a^2 - b^2

so,

x^2 - 1^2.

so,

p(x) = x^2-1.

p(2)= 2^2-1

= 4-1

= 3

p(1)= 1^2-1

= 1-1

= 0

p(0)=0^2-1

= 0-1

= -1

= p(2)×p(1) - p(0).

= 3×0 - (-1)

= 0+1

= 1

Hope this helps you....

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