p(x) = (x-1) (x + 1), then the value
p (2) p (1) - p (o)
Answers
Answered by
3
Answer:
p(x)=(x-1)(x+1)
p(x)=x^2-1
Now,
p(0)=0^2-1
=0-1
=-1
Also,
p(1)=1^2-1
=1-1
=0
And,
p(2)=2^2-1
=4-1
=3
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Answered by
0
Answer:
According to the formula,
(a+b) (a-b) = a^2 - b^2
so,
x^2 - 1^2.
so,
p(x) = x^2-1.
p(2)= 2^2-1
= 4-1
= 3
p(1)= 1^2-1
= 1-1
= 0
p(0)=0^2-1
= 0-1
= -1
= p(2)×p(1) - p(0).
= 3×0 - (-1)
= 0+1
= 1
Hope this helps you....
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