Question

p(x)=(x+1)(x+2)

find the zero

Answer 1

Answer:

x(x+2)+1(x+2)

x^2+2x+x+2

x^2+3x+2

x^2+2x+1x+2

x(x+2)+1(x+2)

(x+1)(x+2)

x=-1 and x=-2

therefore, the two zeros are -1 and -2