Question

the product of two consecutive even integers is 128 ,the quadratic equation to find the integers is.
A)x square+2x-128=0
B)x square+x-128=0
C)x square - 2x-128 =0
D)x square+2x= -128​

Answer 1

Answer:

x2+x-128

Step-by-step explanation:

{x}{x+2}=128

x2+2x=128

x2+2x-128=0

Answer 2

Answer:

(A) is right

Step-by-step explanation:

Let the consecutive number be n and n+2.

then it's products be (n) (n+2)

=> n^2+ 2n = 128

=> n^2 +2n- 128=0