p(x)=(x-2)^2-(x+2)^2
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GIVEN
p(x) = (x - 2)^2 - (x + 2)^2
P (x) = (x^2 - 2x + 1) - (x^2 + 2x + 4)
= x^2 - 2x + 1 - x^2 - 2x - 4
= - 4x - 3
= - (4x + 3)
p(x) = (x - 2)^2 - (x + 2)^2
P (x) = (x^2 - 2x + 1) - (x^2 + 2x + 4)
= x^2 - 2x + 1 - x^2 - 2x - 4
= - 4x - 3
= - (4x + 3)
Answered by
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using identities =
so,
p(x)=[x-2+x+2][x-2-x-2]
p(x)=2x*-4
p(x)=-8x
now,let -8x=0
so,x=8
so,
p(x)=[x-2+x+2][x-2-x-2]
p(x)=2x*-4
p(x)=-8x
now,let -8x=0
so,x=8
rohansinghsuraj:
identity=(a+b)^2-(a-b)^2
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