Solve.
5(x+1)=25
5p+7=19-29
If x=2,y=3 and z=-1 then how to solve
2x+3y-4z
Answers
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2x+3y-4z
=2(2+1)+3(3)-4(-1)=4+2+9-4=9
Answered by
1
Heya Friend ✋✋✋
Your answer is....
Solve ...
(1)....
5 × ( x + 1 ) = 25
5x + 5 = 25
5x = 20
x = 4
(2)....
5p + 7 = 19 - 29
5p = - 10 + 3
p = -7/5
(3)....
If x = 2 , y = 3 and z = -1
Then , 2x + 3y - 4z = ?
Substituting the values of x , y and z
= ( 2 × 2 ) + ( 3 × 3 ) - ( 4 × -1 )
= 4 + 9 + 4
= 17
Hope it helps
Your answer is....
Solve ...
(1)....
5 × ( x + 1 ) = 25
5x + 5 = 25
5x = 20
x = 4
(2)....
5p + 7 = 19 - 29
5p = - 10 + 3
p = -7/5
(3)....
If x = 2 , y = 3 and z = -1
Then , 2x + 3y - 4z = ?
Substituting the values of x , y and z
= ( 2 × 2 ) + ( 3 × 3 ) - ( 4 × -1 )
= 4 + 9 + 4
= 17
Hope it helps
BrainlyHulk:
thanks for marking my answer as brainliest
it's ok
=_=
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