p(x)=x*2-5x-6 find p(0),p(-l),p(-2)'p(-3)
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Answered by
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Hi ,
It is given that ,
p( x ) = x² - 5x - 6 ---( 1 )
i ) p( 0 ) = 0² - 5 × 0 - 6
= -6
ii ) p( - 1 ) = ( - 1 )² - 5 × ( - 1 ) - 6
= 1 + 5 - 6
= 0
iii ) p( - 2 ) = ( -2 )² - 5 × ( - 2 ) - 6
= 4 + 10 - 6
= 14 - 6
= 8
iv ) p ( - 3 ) = ( -3 )² - 5 ( -3 ) - 6
= 9 + 15 - 6
= 24 - 6
= 18
I hope this helps you.
: )
It is given that ,
p( x ) = x² - 5x - 6 ---( 1 )
i ) p( 0 ) = 0² - 5 × 0 - 6
= -6
ii ) p( - 1 ) = ( - 1 )² - 5 × ( - 1 ) - 6
= 1 + 5 - 6
= 0
iii ) p( - 2 ) = ( -2 )² - 5 × ( - 2 ) - 6
= 4 + 10 - 6
= 14 - 6
= 8
iv ) p ( - 3 ) = ( -3 )² - 5 ( -3 ) - 6
= 9 + 15 - 6
= 24 - 6
= 18
I hope this helps you.
: )
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