Question

p(x)=x^+2x+1 plzz answer me​

Answer 1

p(-1) is the answer

because the p(X)=0 in that condition.

Even it's a quadratic equation delta= b^2 -4ac =0

so both roots or zeros are equal to -1

using the formula

-b±√(b^2 -4ac) / 2a

we get the answer

Answer 2

The answer is (x+1)(x+1)

Step-by-step explanation:

To solve the quadratic equation x²+2x+1

we know that p(x) = x² - (α+β)x+αβ

Sum of the zeros is α+β

From the given equation,

The Sum of the zeros  is the coefficient of x

Sum = 2

The Product of the zeros is the constant value

Product = 1

The two numbers which are added, we have to get 2

The two numbers which are multiplied, we have to get 1

Let, the two numbers be x and y

x+y =2

xy=1

x=1 and y=1

Apply these values in the given equation

x and y are the coefficients of x

==>x²+2x+1

The equation will become

==>x²+1x+1x+1

Divided into two halves and taking the values as common

==> x(x+1) +1(x+1)

The factors of the polynomial is (x+1)(x+1)

x=-1 and x=-1