Math, asked by pramod789, 1 year ago

p[x]=√x^3+1 is not a polynomial give reason

Answers

Answered by rsd742679
68

Answer:

Because it has root

Step-by-step explanation:

Hope that helps you

Answered by chachi4201
5

A polynomial is defined as an expression which is composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, multiplication and division (No division operation by a variable).

Integer, whole-valued positive or negative number or 0. The integers are generated from the set of counting numbers 1, 2, 3,… and the operation of subtraction. When a counting number is subtracted from itself, the result is zero; for example, 4 − 4 = 0.

According to the question

p(x)=\sqrt{x^{3}+1}

So, p(x)=\sqrt{x^{3}+1} is not a polynomial because the exponents of x is not a positive integer.

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