Question

p(x) = x^3 + 4x^2 + 9 divided by g(x) = x - 20​

Answer 1

Answer:

By remainder theorem:-

$\bf \: p(x) = {x}^{3} - {4x}^{2} + 9$

$\bf \: g(x) = x - 20$

$\bf \: g(x) = 0$

$\bf \: x - 20 = 0$

$\bf \: x = 20$

$\bf \red{sub \: x = 20 \: in \: p(x)}$

$\bf \: p(x) = {x}^{3} - {4x}^{2} + 9$

$\bf \: p(20) = {(20)}^{3} - 4( {20)}^{2} + 9$

$\bf \: p(20) =800 - 4(400) + 9$

$\bf \: p(20) =800 - 1600 + 9$

$\bf \: p(20) = - 800 + 9$

$\bf \: p(20) = - 791$

$\bf \green{remainder \: is \: - 791}$

$\bf \huge \red{Indian} \blue{♡} \green{Army}$