Question

p(x)=x^3+ax^2-x+b
find the relation between a and b for x-1 to be a factor of p(x)

Answer 1

Answer:

X³+AX²-X+B

AND , X-1 = 0

==> X = 1

SO, PUTTING VALUE OF X IN POLYNOMIAL

==> (1)³+A(1)²-1+B = 0

==> 1 + A - 1 + B  = 0

==> 0+A+B = 0

==> A+B = 0