Question

P(x)=x-x²-1 find zeros of this polynomial

Answer 1

Step-by-step explanation:

Firstly rearrange it in the order of degree

p(x)= -x2+x-1

D=b2-4ac

Here, a=-1 , b=1 ,c=-1

D= (1)2-4(-1)(-1)

=1+4(-1)

=1+(-4)

=1-4=-3

Since D is less than zero

This equation have no solution