Math, asked by katariyasumit, 8 months ago

p(x) = x2 - 1, x=1,-1​

Answers

Answered by devansh96kkr
5

Step-by-step explanation:

p(x) = x2-1 , x= 1,-1

1ST CASE (WHEN X=1)

P(1) = 1×2-1

P(1) = 2-1

P(1) = 1

_____________________

2ND CASE (WHEN X=-1)

P(-1) = -1×2-1

P(-1) = -2-1

p(-1) = -4

Answered by varunammachilukuri
9

Step-by-step explanation:

p(x) = x^2 - 1; x= 1,-1

p(1) = 1^2 - 1

= 1-1

=0

p(-1)=(-1)^2 -1

=1 -1

=0

both the values are zeroes of the given question.

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