Question

p(x) = x² - 2xFind p(0), p(1), p(2) for the above polynomial.

Answer 1

Answer :

Given that,

p (x) = x² - 2x

Then,

p (0) = 0² - 2 (0) = 0 - 0 = 0,

p (1) = 1² - 2 (1) = 1 - 2 = - 1 and

p (2) = 2² - 2 (2) = 4 - 4 = 0

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Answer 2

Hi ,

Given p(x) = x² - 2x

1 ) p(0) = 0² - 2 × 0 = 0

2 ) p(1) = 1² - 2 × 1 = 1 - 2 = -1

3 ) p(2) = 2² - 2 × 2 = 4 - 4 = 0

Therefore ,

p(0) = 0 ,

p(1) = -1 ,

p(2) = 0

I hope this helps you.

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