Question

p(x)=x2+3x-18 Find the Zero of the polynomial and make relationship with its coefficient.

A verified Answer pls​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

$\alpha = -6\\\beta = 3$

Explanation:

$= x2-9x+3x-18\\= x (x+6) -3 (x+6)\\= (x+6) (x-3) = 0\\= x + 6 =0\\= x =-6\\\\= x-3=0\\= x=3\\= \alpha = -6; \beta =3$

=> Sum of Zeroes

= -6 + (3) = -3

=> Product of Zeroes

= (-6) (3) = -18

$= x2 + 3x-18\\= ax2+bx+c\\= a=1,b=3,c=-18\\= \alpha +\beta = -b/a\\= \alpha + \beta = -3/2\\= \alpha +\beta = c/a\\= \alpha \beta = -18/1 = -18$