Question

p(x)=x2-5x-6,find the value of p(1),P(2),p(3)p(0),p(-1)p(-2)p(-3)

Answer 1

Heya !!



P ( X ) = X² - 5X - 6



P (1) = (1)² - 5 × 1 - 6 = 1 - 5 - 6 = 1 - 11 = -10



P (2) = (2)² - 5 × 2 - 6 = 4 - 10 - 6 = 4 - 16 = -12


P (3) = (3)² - 5 × 3 - 6 = 9 - 15 - 6 = 9 - 21 = -12.



P (0) = (0)² - 5 × 0 - 6 = 0 - 0 - 6 = -6


P (-1) = (-1)² - 5 × -1 - 6 = 1 + 5 - 6 = 6 - 6 = 0




P (-2) = (-2)² - 5 × -2 - 6 = 4 + 10 - 6 = 14 - 6 = 8



P (-3) = (-3)² - 5 × -3 - 6 = 9 + 15 - 6 = 24 - 6= 18

Answer 2

HEYA!!
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P( X ) = X^2 - 5 X - 6

1). P ( 1 )

= (1)^2 - 5 - 6

= 1 - 5 - 6

= -10



2). P(2)

= 4 - 10 - 6

= 4 - 16 = -12

3). P(3)

= 9 - 15 -6

= 9 - 21

= -12

4). P (0)

= 0 - 6 = -6


5). P(-1)

= 1 + 5 -6

= 0

6). P ( -2)

= 4 +10 -6

= 14 - 6 = 8


7). P ( -3)

= 9 +15 -6

= 18.


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