Question

p(x) = x²- 5x - 6, find the values of p(1), p(2), p(3), p(0), p(-1), p(-2), p(-3)

{answer should be short and answer should be in attachment.}​

Answer 1

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Answer 2

p(x) = x²- 5x - 6

now

p(1)=1-5-6

=-10

p(2)=4-10-6

=-12

p(3)=9-15-6

=-12

p(0)=0-0-6

=-6

p(-1)=1+5-6

=0

p(-2)=4+10-6

=8

p(-3)=9+15-6

=18

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