p(x)= x²-5x – 6, find the values
of P(1),p(2), P (3), P(0),p(-1),p(-2),p(-3)?
Answers
Answered by
0
Step-by-step explanation:
p(x) =x²-5x-6
P(x) =1
p(1)=1²-5×1-6
=1-5-6
=-10
p(x) =2
P(2)=2²-5×2-6
=4-10-6
=-6
p(x) =3
.............
Answered by
2
Answer:
➡️ p(x) = x² - 5x - 6
➡️ p(x) = 1
= (1)² - 5(1) - 6
= 1 - 5 - 6
= 1 - 11
= -10
➡️p(x) = 2
= (2)² - 5(2) - 6
= 4 - 10 - 6
= - 6 - 6
= -12
➡️ p(x) = 3
= (3)² - 5(3) - 6
= 9 - 15 - 6
= -6 -6
= -12
➡️p(x) = 0
= (0)² - 5(0) - 6
= 0 - 0 - 6
= -6
➡️ p(x) = -1
= (-1)² - 5(-1) - 6
= 1 - (-5) - 6
= 1 + 5 - 6
= 6 - 6
= 0
hope it helps uh...!!
answered by :
⚡Rajula Ravalika⚡
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