Question

p(x)=x²+5x+6.....find the zeroes of the given polynomials ​

Answer 1

Answer:

Solution :

p(x) = x² - 5x - 6

i ) p(1) = 1² - 5(1) - 6

= 1 - 5 - 6

= 1 - 11

= -10

ii ) p(2) = 2²-5(2) - 6

= 4 -10 - 6

= -12

iii ) p(3) = 3² - 5(3) - 6

= 9 - 15 - 6

= -12

iv ) p(0) = 0² - 5(0) - 6 = -6

v ) p(-1) = (-1)² - 5(-1) - 6

= 1 + 5 - 6

= 0

v ) p(-2) = (-2)² - 5(-2) - 6

= 4 + 10 - 6

= 8

vi ) p(-3) = (-3)² - 5(-3) - 6

= 9 + 15 - 6

= 18

•••••

Explanation: