Question

p(x)=x²-7x+12 check whether x=4 is a zero of p(x)​

Answer 1

Answer:

p(x) = x^2 - 7x + 12 .....................(1)

Now , x = 4 ...................................(2)

Put eq. (2) in eq. (1) ,

= (4) ^ 2 - 7(4) + 12

= 16 - 28 + 12

= 28 - 28

= 0

Sice the answer is coming zero

This implies that x = 4 is a zero of the given equation.