Question

p(x)= x²-9x+20 (i) Find the zeroes of p(x).​

Answer 1

Answer:

Zeroes of p(x) will be 4 and 5.

Step-by-step explanation:

p(x)= x2-9x+20

p(x)= x2-5x-4x+20

p(x)= x(x-5)-4(x-5)

p(x)= (x-4)(x-5)

x-4 and x-5 are the factors of p(x)

Therefore zeroes are 4 and 5

Answer 2

Answer:

zero are 4 and 5 *******!!!