Question

p(x)=x²-x +1, Find p(0), p(1) and p(2) for each of the give polynomial.

Answer 1

p(0)= 0-0+1=1

p(1)=1-1+1=1

p(2)=4-2+1=3

Answer 2

Given p(x) = x² - x + 1

i ) p(0) = 0² - 0 + 1 = 1

ii ) p(1) = 1² - 1 + 1 = 1

iii ) p(2) = 2² - 2 + 1

= 4 - 2 + 1

= 3

Therefore ,

p(0) = 1 ,

p(1) = 1 ,

p(2) = 3

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