p(x)=x2-x-6 sum and zeroes and relation
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given xpower2-x-6
therefore xpower2-3x+2x-6=0
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
therefore(x-3)=0 (or)(x+2)=0
that is X=3 or x=-2
Sum of the zeros=3+(-2)=1= -(coefficent of x) / coefficent of x power2)
product of zeroes=3*-2=-6= (constant) / (coefficent of xpower2)
therefore xpower2-3x+2x-6=0
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
therefore(x-3)=0 (or)(x+2)=0
that is X=3 or x=-2
Sum of the zeros=3+(-2)=1= -(coefficent of x) / coefficent of x power2)
product of zeroes=3*-2=-6= (constant) / (coefficent of xpower2)
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