Question

p(x)=x³-1,x=1 Verify whether the expression is zeros of the polynomial indicated against them, or
not.

Answer 1

☺️Hey mate! here's your answer!☺️

since,

p(x) = x³ - 1

and, x = 1,

so substituting value of x in the equation,

p(1) = (1)³ - 1

p(1) = 1 - 1

p(1) = 0 ....Answer!

thus, it is proved that (x + 1) is the factor of p(x).

hope it is helpful ✌️!

Answer 2

Answer:

x = 1 is a zero of the given polynomial.

Step-by-step explanation:

In the question, the expression is

$P(x) = x^{3}\ -\ 1$    ............(i)

putting x = 1 in eq. (i)

$P(1) = 1^{3}\ -\ 1$

= 1 - 1

= 0

∴ P(1) = 0.

Therefore, x = 1 is a zero of the given polynomial.