Question

p(x)=x³-2x²+5x
find the zeros​

Answer 1

Answer:

x^3 -2x^2 +5x=x(x^2 -2x +5)=0

x=0 and (x^2 -2x +5)=0, comparing with ax^2 +bx +c=0 we have,

a=1 , b=-2 , c=5, Now D=b^2 -4ac= (-2)^2 -4*1*5=4-20=-16<0 so no other real zeros for the  function

so x=0 is the only real solution for the function.

Step-by-step explanation:

Answer 2

p(x) = x³ - 2x² + 5x

To find the zeroes the p(x) must be equal to 0

0 = x³ - 2x² + 5x

0 = x(x² - 2x + 5)

Now either x = 0 or x² - 2x + 5 = 0

So first zero is x = 0

2nd zero

x² - 2x + 5 = 0

a = 1, b = -2 and c = 5

Where the form of equation is

ax² + bx + c = 0

Discriminant to find the zero is

D = b² - 4ac

= (-2)² - 4(1)(5)

= 4 - 20

= -15

Since D < 0 therefore no real root is possible

Henceforth

Zero of p(x) is x = 0

Hope this helps