Question

 p(x) = x3 + 4x + 16 is divided by x + 2 , then find the remainder and hence determine whether x + 2 is a factor of p(x) or not . also in this question in x3 is 3 is a cube​

Answer 1

Answer:

x^3+4x+16÷x+2

x+2=0

x=0-2

x=-2

p(x)=x^3+4x+16

p(-2)=(-2)^3+4(-2)+16

-8-8+16

0

Therefore, remainder is 0 and also x+2 is a factor of x^3+4x+16.

Step-by-step explanation:

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