Question

p(x)=x³-6x²+11x-6;x=1,2,3​

Answer 1

Answer:

f(1)=0

f(2)=0

f(3)=0

so we can conclude that X=1,2,3are the roots of the equation

Answer 2

Step-by-step explanation:

p(1)=1 -6+11-6=12-12=0

and p(2)=8-24+22-6=30-30

and ifx=3

p(3)=27-54+33-6=60-60=0.

hence:x={1,2,,3}.

p(x)=0 ans