Math, asked by nachiketstpatil9381, 1 year ago

P(x) = x3-px2+2xthen find the value of p(1)

Answers

Answered by anua2003
1

putting 1 in the place of x in

x3-px2+2=0,


1-p+2=0

-p+1=0

-p= -1

p=1

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