Question

P(x)=x⁴+ a²x²-3x-a factor (x+a)=0​

Answer 1

Answer:

The required "option A) 0" is correct.

Step-by-step explanation:

Given,

Let (x + a) is a factor of P(x) : x^4x

4

- a^2x^2a

2

x

2

+ 3x - 6a

To find, the value of a in the given poynomial.

∵ x + a = 0

⇒ x = - a

Put x = - a in the given polynomial, we get

P(- a) = 0

⇒ (-a)^4(−a)

4

- a^2(-a)^2a

2

(−a)

2

+ 3(- a) - 6a = 0

⇒ a^4a

4

- a^4a

4

- 3a - 6a = 0

⇒ - 3a - 6a = 0

⇒ - 9a = 0

⇒ a = 0

Thus, the required "option A) 0" is correct