Question

p(x) =x4-x2-12,g(x)=x+2​

Answer 1

$\mathfrak{\huge{\red{QUESTION}}}$

$if \: \: p(x) \: \: = {x}^{4} - {x}^{2} - 12$

and

$g( x) \: = \: x \: + 2 \: \\ \\ so \: \: x + 2 = 0 \\ \\ = \geqslant x = - 2$

If P(x) is divided by (x + 2) then the remainder is p(-2)

$p(x) = {x}^{4} - {x}^{2} - 12 \\ \\ = \geqslant p( - 2) = ( -2) {}^{4} - ( - 2) {}^{2} - 12 \\ \\ = \geqslant p = 16 - 4 - 12 \\ \\ = \geqslant p = 16 - 16 \\ \\ = \geqslant p = 0$

$\mathfrak{\huge{\red{Answer}}}$

Answer 2

Answer:

f(-2)=(-2)⁴-(-2)²-12

f=16-4-12

f=12-12

f=0