P(x, y) is a point which divides line segment joining A(2, 1) and B(5, -8) in 1:2 ratio. Find
the point P. Hence find ‘k’ if point ‘P’ lies in the line 2x – y + k = 0.
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Answered by
1
Answer:
Given that P (x,y) divides the line segment joing A (1,1) and B (5,8)
AP:AB=1:3
AP:PB =1:2
2x-y+k =0
2 (3)-(-2)+k =0
6+2+k=0
k=-8 .
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Answer:
↪️ k = -8.
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