p(y)=y^2-2y+5 find p(2)
Answers
Answered by
1
hey the answer is. ....
p (2 ) = 2^2 - 2 × 2 + 5
= 4 - 4 + 5
= 5
hope it helps uu frnd
p (2 ) = 2^2 - 2 × 2 + 5
= 4 - 4 + 5
= 5
hope it helps uu frnd
Answered by
0
P(y)=y^2-2y+5
=(2)^2-(2×2)+5
=4-4+5
=4+1
=5
Therefore,
P (2) = 5
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