Question

p(y) = y2 – 2√2y + 1, then find the value of p (2√2 )​

Answer 1

Answer:

p(2√2)=1

Step-by-step explanation:

p(y)=y²-2√2y+1

 Now y=2√2 (given)

p(2√2)=(2√2)²- 2√2(2√2)+1

            =8-8+1

∴p(2√2)=1

Thus ,the value of p(2√2)=1.