p10+p4q6 please evaluate this
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Answer :
Now, p¹⁰ + p⁴q⁶
= p⁴ (p⁶ + q⁶)
= p⁴ {(p²)³ + (q²)³}
= p⁴ (p² + q²) {(p²)² - p²q² + (q²)²}
= p⁴ (p² + q²) (p⁴ - p²q² + q⁴),
which is the required factorization.
Identity rule :
x³ + y³ = (x + y) (x² - xy + y²)
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Now, p¹⁰ + p⁴q⁶
= p⁴ (p⁶ + q⁶)
= p⁴ {(p²)³ + (q²)³}
= p⁴ (p² + q²) {(p²)² - p²q² + (q²)²}
= p⁴ (p² + q²) (p⁴ - p²q² + q⁴),
which is the required factorization.
Identity rule :
x³ + y³ = (x + y) (x² - xy + y²)
#MarkAsBrainliest
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