Math, asked by rupam068, 6 months ago

(p2+q2) (p+q) +(p2+q2) (2p-q)

Answers

Answered by krishnas10
3

Step-by-step explanation:

(p^2+q^2)(p+q) + (p^2+q^2)(2p-q)

(p^3 + pq^2 + p^2q + q^3) + (2p^3 + 2pq^2 - p^2q - q^3)

p^3 + pq^2 + p^2q + q^3 + 2p^3 + 2pq^2 - p^2q - q^3

p^3 + 2p^3 + pq^2 + 2pq^2 + p^2q - p^2q + q^3 - q^3

3p^3 + 3pq^2

3p(p^2 + q^2)

Answered by manojkrsingh1171
0

Answer:

Step-by-step explanation:

(p^2+q^2)(p+q) + (p^2+q^2)(2p-q)

(p^3 + pq^2 + p^2q + q^3) + (2p^3 + 2pq^2 - p^2q - q^3)

p^3 + pq^2 + p^2q + q^3 + 2p^3 + 2pq^2 - p^2q - q^3

p^3 + 2p^3 + pq^2 + 2pq^2 + p^2q - p^2q + q^3 - q^3

3p^3 + 3pq^2

3p(p^2 + q^2)

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