(p²+q²-r²)²- 4p²q² solve
Answers
Answered by
1
Answer:
(p
2
+q
2
−r
2
)−(2pq)
2
=(p
2
+q
2
−r
2
+2pq)(p
2
+q
2
−r
2
−2pq)
=(p
2
+q
2
+2pq−r
2
)(p
2
+q
2
−2pq−r
2
)
=[(p+q)
2
−r
2
][(p−q)
2
−r
2
]
=(p+q+r)(p+q−r)(p−q+r)(p−q−r)
Answered by
1
Answer:
(p+q+r)(p+q-r)(p-q+r)(p-q-r)
Step-by-step explanation:
(p2+q2-r2)2-4p2q2
(p2+q2-r2)2-(2pq)2
(p2+q2-r2+2pq)(p2+q2-r2-2pq)
[(p+q)2-r2][(p-q)2-r2]
(p+q-r)(p+q+r)(p-q-r)(p-q+r)
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