Question

(p²+q²+r²) (pq+qr);p=2,q=-3,r=1
Solve this problem....​

Answer 1

Answer:

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Step-by-step explanation:

your answer is attached

Answer 2

Answer:

Here, The answer is (-126).

Step-by-step explanation:

Here, As per our given question,

=(p^2+q^2++r^2)(pq+qr) ,(Where, p=2,q= -3,r=1)

So,=[(2^2)+(-3)^2+(1)^2) [(2×-3)+(-3×1)]

=(4+9+1)[(-6)+(-3)] (Here, (-3)×(-3)=9,because minus×minus=plus)

=(14) ×(-9)

=(-126)

Hence, (-126) is the answer.

Thank you.