(p²+q²+r²) (pq+qr);p=2,q=-3,r=1
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Answered by
1
Answer:
Here, The answer is (-126).
Step-by-step explanation:
Here, As per our given question,
=(p^2+q^2++r^2)(pq+qr) ,(Where, p=2,q= -3,r=1)
So,=[(2^2)+(-3)^2+(1)^2) [(2×-3)+(-3×1)]
=(4+9+1)[(-6)+(-3)] (Here, (-3)×(-3)=9,because minus×minus=plus)
=(14) ×(-9)
=(-126)
Hence, (-126) is the answer.
Thank you.
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