Question

p²q – p r² – pq + r²
Factorise

Answer 1

p²q - pr² - pq + r²


=> p( p - r² ) -( p - r² )

=> ( p - r² ) ( p - r² )

Answer 2

Answer:

(pq-r²)(p-1)

Step-by-step explanation:

Factorization is the process of expressing a mathematical term into a product of two or more simplified mathematical terms. Those two or more simplified terms are called the factors of the original term.

We are asked to factorize the expression (p²q-pr²-pq+r²).

Now, p²q-pr²-pq+r²

= p(pq-r²)-1.(pq-r²)

=(pq-r²)(p-1)

Hence, this is the required factorization and (pq-r²) and (p-1) are called the factors of (p²q-pr²-pq+r²). (Answer)